If the original side length is "s" and the original slant height is "h", the original surface area is
.. S = (base area) +(lateral area)
.. S = s² +(1/2)*(4s)*h
.. S = s(s +2h)
Now, if we make these replacements: s ⇒ 3s, h ⇒ h/5, we have
.. S' = (3s)(3s +2h/5)
.. S' = 9s² +(6/5)s*h . . . . . . . the formula for the modified area (in terms of original dimensions)
_____
Of course, in terms of the modified dimensions, the formula is the same:
.. S' = s'(s' +2h')
192
i did that test before
70 x P = 63
P=63/70 = 0.9
Since P is 1-the discount
1-discount= 0.9
discount is 0.1, or 10 %
Find the slope, m, of the line whose graph contains the points (1,2) and (2, 7). ... What does it mean if the slope, m, is negative in y = mx + b?
