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2 years ago

Question 3 Show work and solve 3 = 5*+1 using change of base formula.

Mathematics

1 answer:

Romashka [77]2 years ago

7 0

Answer: $x=\frac{\log (3/5)}{\log 5}$

Step-by-step explanation:

$3=5^{x+1}\\\\\log_{5} 3=x+1\\\\x=\log_{5} 3-1\\\\x=\log_{5} 3-\log_{5} 5\\\\x=\log_{5} \left(\frac{3}{5} \right)\\\\x=\frac{\log (3/5)}{\log 5}$

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How do we say the expression in words? can somebody help me pls rn

UNO [17]

Answer:

Step-by-step explanation:

1 Escritura unida

Según la NGLE se unen las palabras que se interpretan como una unidad y en las que, por tanto, la marca de plural solo afecta al último elemento:[1]

el bajorrelieve, los bajorrelieves

la mediapunta, las mediapuntas

En un buen número de casos, el primer elemento puede seguir teniendo individualidad para parte de los hablantes y admitir la marca del plural. La Gramática admite algunos de esos casos, de modo que las dos formas son posibles, que se escribirán unidas o separadas según se dé ese plural o no:

el puercoespín, los puercoespines; el puerco espín, los puercos espines

el arcoíris, los arcoíris; el arco iris, los arcos iris

el medioambiente, los medioambientes; el medio ambiente, los medios ambientes.

el pavorreal, los pavorreales; el pavo real, los pavos reales

La Gramática prefiere, como norma general, la forma en una palabra.

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3 years ago

The price of a computer was decreased by 7% to £500. What was the price before the decrease? Give your answer to the nearest pen

Katarina [22]

Answer:

537.64

Step-by-step explanation:

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3 years ago

If r = 7 units and x = 9 units, then what is the volume of the cylinder shown above?

Marianna [84]

Idk if the hight is 9 units but if it is the answer is 1385.44 units cubed.

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3 years ago

A mass oscillating up and down on the bottom of a spring can be modeled as harmonic motion. if they weight is displaced a maximu

snow_tiger [21]

9514 1404 393

Answer:

1.63 cm (across the centerline from release)

Step-by-step explanation:

If we assume time starts counting when we release the weight from its fully-extended downward position, then the position at 1.15 seconds can be found from ...

h(t) = -7cos(2πt/4)

h(1.15) = -7cos(π·1.15/2) = -7(-0.233445) ≈ 1.63412 . . . cm

That is, 1.15 seconds after the weight is released from below the resting position, it will be 1.63 cm above the resting position.

If it is released from above the resting position, it will be 1.63 cm below the resting position at t=1.15 seconds.

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3 years ago

How to graph f(x)=100(0.7)

inn [45]

The graph is a horizontal line at 70 units above the x-axis and parallel to it. f(x) doesn't depend on the value of 'x'. It's always 70.

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3 years ago