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DanielleElmas [232]
3 years ago
9

4. Seven times the difference of a number k and five is twenty-onel

Mathematics
1 answer:
laila [671]3 years ago
4 0

Answer:

k = 8

Step-by-step explanation:

7(k - 5) = 21

k - 5 = 3

k = 8

Hope this helps!

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What is the slope of the line that passes through the points (−10,−8) and (-8, -16) Write your answer in simplest form.
jarptica [38.1K]

Step-by-step explanation:

given,

point = ( -10, -8 ) and ( -8, -16 )

we know,

slope = y2 - y1 / x2 - x1

x1 , y1 = (-10 , -8 )

x2 , y2 = ( -8, -16 )

after inserting the values we got,

→ -16 - (-8 ) / -8 - (-10)

→ -8/2 → -4

therefore, slope of line is -4.

hope this answer helps you dear...take care and may this answer helps you dear!.

7 0
3 years ago
ram is half his fathers age now. ten years ago he was one third his fathers age then what are their present ages
NeX [460]

x   -  Ram's age now

Ram is half his father's age now, so his father's age is two times Ram's age:

2x  - Ram's father age now

x - 10   -  Ram's age ten years ago

2x - 10    - Ram's father age ten years ago

ten years ago he was one third his father's age so his father's age was three times Ram's age:

2x - 10 = 3•(x - 10)

2x - 10 = 3x - 30

-10 + 30 = 3x - 2x

20 = x

2x = 2•20 = 40

Answer:

<u>Ram is 20 years old now, Ram's father is 40 years old now.</u>

8 0
3 years ago
The population of a city is expected to increase by 7.5% next year. If p represents the current population, which expression rep
Elodia [21]
p+0.075p=1.075p
7 0
3 years ago
Read 2 more answers
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
3 years ago
Please help, Geometry I have NO idea how to do this. (#17, #20)
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The image is answer.................

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