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Naddik [55]
3 years ago
9

If a right circular cone is intersected by a plane so that the intersection goes through the cone’s vertex as well as an edge of

each nappe, as in the picture below, what shape is produced?

Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0

Answer:

It is C.

Step-by-step explanation:

Im finding it a bit difficult to put it into words - but you can picture it in your brain. It is a line. The plane is just touching the surface of the cones.

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Some find slope please?
Andre45 [30]

Answer:

3/4

Step-by-step explanation:

Use slope formula y2-y1 over x2-x1

9-3=6

5--3 becomes 5+3 which equals 8

so 6/8

which when simplified is 3/4.

4 0
3 years ago
A group of 30 students from your school is part of the audience for a TV game show. The total number of people in the audience i
s344n2d4d5 [400]

Answer:

5.3%

Step-by-step explanation:

The final probability is calculated by means of the quotient of the specific combinations and the total of total combinations

Let's start with the specific ones,

First the number of combinations of 4 of the 30 students getting a spot, i.e .:

A combinations are equal to:

nCx = n! / x! * (n-x)!

Replacing:

30C4 = 30! / (4! * 26!) = 27405

Segundo the number of combinations of the other audience members filling the other 4 (8-4) spots n = 110, 140 - 30

110C4 = 110! / (4! * 106!) = 5773185

Now the total combinations of possible 8 contestants from the audience

140C8 = 140! / (8! * 132!) = 2.98 * 10 ^ 12

Finally, the probability is equal to:

P = (30C4 * 110C4) / 140C8

replacing:

P = 27405 * 5773185 / 2.98 * 10 ^ 12

P = 0.053

Therefore the probability is 5.3%

4 0
3 years ago
What is the approximate circumference of the circle shown below?​
aniked [119]

Answer:

D: 109 cm

Step-by-step explanation:

The formula of circumference is

\pi d

Diameter =

17.4 \times 2 = 34.8

Hence, circumference =

34.8 \times \pi = 109.32742...

rounded of to 109.

8 0
3 years ago
Read 2 more answers
HELP HELP!!
Goryan [66]

Answer:

0

Step-by-step explanation:

p_1:~~y = x^2+2\\p_2:~~y = 3x^2+2\\ \\ V{p_1} = \Big(-\dfrac{b}{2a}, -\dfrac{\Delta}{4a}\Big) = \Big(-\dfrac{0}{2}, -\dfrac{0^2-4\cdot 2}{4}\Big) = \Big(0,2\Big) \\ \\ Vp_2 = \Big(x_V, -\dfrac{\Delta}{4a}\Big) = \Big(0, -\dfrac{0^2-4\cdot 3 \cdot 2}{4\cdot 3}\Big) = \Big(0,2\Big) \\ \\ \\ \text{The distance is }0,~~\text{Because the vertices are equal.}

7 0
3 years ago
Help help help help help
Irina18 [472]
Sometimes never always always
5 0
2 years ago
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