-2y^2 + 6y + 2 = 0
a = -2, b = 6, c = 2
x = (- b + - sqrt(b^2-4ac))/(2a)
x=(-6+-sqrt(36-4*-2*2))/-4
x=(-6+-sqrt(36+16))/-4
x=(-6+-sqrt(52))/-4
x = (-6 +- 2sqrt13)/-4
x = (3 + - sqrt13)/2
Answer: 2+3
Step-by-step explanation:
Leg one: x (shorter side)
Leg two: x+6
Hypotenuse: 2x-6
Use a^2+b^2=c^2
x^2+(x+6)^2=(2x-6)^2
x^2+x^2+12x+36=4x^2-24x+36
2x^2+12x=4x^2-24x
36x=2x^2
36 = 2x
x = 18
Answer:
1/5
Step-by-step explanation:
change in height over change in horizontal run. Which is 10 ft/2ft or 1/5
Using the Pythagorean therom.
81 + b^{2} = 196
b^{2} = 115
b =
Hope this helps!
