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nekit [7.7K]
3 years ago
10

rectangular piece of board is 61.8 centimeters by 84.9 centimeters. What is the perimeter of the piece of board?

Mathematics
1 answer:
rjkz [21]3 years ago
3 0

Answer:

293.4cm

Step-by-step explanation:

Perimeter = 2(L + W)

= 2(61.8 + 84.9)

= 2 x 146.7

= 293.4cm

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Linda purchased a used vehicle that depreciates under a straight line method. The initial value of the car is $7000, and the sal
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Answer:

The value at the end of year 2 is $4400.

Step-by-step explanation:

The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.

A line is given by

y = mx + b

where m is the slope and b the bias (aka y-intercept).  You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:

y = -\frac{6500}{5}x+7000

and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:

y=-\frac{6500}{5}\cdot 2 + 7000= 4400

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3 years ago
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(X^3 + 2x^2-x-2)/(x+2)=?
ankoles [38]

the correct answer is A.

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Answer:

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Step-by-step explanation:

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Write a function equation that represents a line that contains the two points (-3, 5) and (2, 10).
Eva8 [605]

Step-by-step explanation:

1. 1st of all calculate the gradient

( - 3, 5) ( 2, 10)

Gradient = (10 - 5) / ( 2--3)

= 1

2. Then find the eq

Y = mx + c

Where m is the gradient

y= 1x + c

Now replace any 2 coordinates from above in the eq.

For ex I'm taking (2, 10)

Y = 1x + c

In the coordinate, x = 2 and y =10

By replacing this in the eq, I will find c

10 = 1(2) + c

2 + c = 10

c = 10 - 2

= 8

So the eq is y = x + 8 ⬅️

4 0
3 years ago
Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15
Digiron [165]

\huge \boxed{\mathfrak{Question} \downarrow}

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{array}  { l  }  { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.

  • To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x-5y=-13, \: 3x+4y=15

  • Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

2x-5y=-13

  • Add 5y to both sides of the equation.

2x=5y-13

  • Divide both sides by 2.

x=\frac{1}{2}\left(5y-13\right)  \\

  • Multiply \frac{1}{2}\\ times 5y - 13.

x=\frac{5}{2}y-\frac{13}{2}  \\

  • Substitute \frac{5y-13}{2}\\ for x in the other equation, 3x + 4y = 15.

3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15  \\

  • Multiply 3 times \frac{5y-13}{2}\\.

\frac{15}{2}y-\frac{39}{2}+4y=15  \\

  • Add \frac{15y}{2} \\ to 4y.

\frac{23}{2}y-\frac{39}{2}=15  \\

  • Add \frac{39}{2}\\ to both sides of the equation.

\frac{23}{2}y=\frac{69}{2}  \\

  • Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{ \underline{ \sf \: y=3 }}

  • Substitute 3 for y in x=\frac{5}{2}y-\frac{13}{2}\\. Because the resulting equation contains only one variable, you can solve for x directly.

x=\frac{5}{2}\times 3-\frac{13}{2}  \\

  • Multiply 5/2 times 3.

x=\frac{15-13}{2}  \\

  • Add -\frac{13}{2}\\ to \frac{15}{2}\\ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

\large\underline{ \underline{ \sf \: x=1 }}

  • The system is now solved. The value of x & y will be 1 & 3 respectively.

\huge\boxed{  \boxed{\bf \: x=1, \: y=3 }}

8 0
2 years ago
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