All categories

2 years ago

A. 25(-5) = ? b. -15(-5) = ?

Mathematics

1 answer:

Ronch [10]2 years ago

7 0

A) -125
b: 75
I hope its help :-D

You might be interested in

I do not know how to do this but I need a answer cuz u don’t know it

Law Incorporation [45]

You answer would be 16.2.

Hope this helps,
♥Nikki♥

3 0

3 years ago

The product of 5 and the cube of x, increase by the difference of 6 and x3

lawyer [7]

Answer:

$4x^{3} +6$

Step-by-step explanation:

The product of 5 and the cube of x

$5*x^3\\\\=5x^3$

the difference of 6 and x^3

$6-x^3$

I understand as increase as sum so

$(5x^3)+(6-x^3)\\\\5x^3+6-x^3\\\\(5-1)x^3+6\\\\4x^3+6$

5 0

2 years ago

What's 1.6 rounded to the nearest tenth

dem82 [27]

Are there anymore numbers after the six? If there is not then it si already rounded to the nearest tenth.

7 0

3 years ago

Read 2 more answers

For what value of x is (2x^2+8x)/(x+4)(x^2-9) undefined?

irakobra [83]

Answer:

The value at x =3 is undefined for the given expression

Step-by-step explanation:

Given expression is $\frac{2x^2+8x}{(x+4)(x^2-9)}$

To find for what value of x is undefined in the given expression :

$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}$

$=\frac{2x}{x^2-9}$

$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}$

If we put x=3 in the above expression we get

$\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}$

$=\frac{6}{9-9}$

$=\frac{6}{0}$

Therefore $\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}$

The value at x =3 is undefined for the given expression

7 0

2 years ago

3x-4>-16 <br>solve this please

Sidana [21]

X > -4 is the answer if you solve for x.

8 0

2 years ago

Read 2 more answers