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goldenfox [79]
3 years ago
14

The table below shows the proportional relationship between the weight of cereal, in ounces, and the number of packs of cereal:

Mathematics
2 answers:
cestrela7 [59]3 years ago
6 0

Answer:

The answer is a

Its a because 13 times 3 is 39

13 times 4 is 52

and 13 times 5 is 65

Credit to: alizahalder2007

brilliants [131]3 years ago
5 0
The answer is a because it is constant
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Answer:

what she sells each t-shirt for.

Step-by-step explanation:

if f(x) is the profit and x=# of t-shirts,

the rate of change is 8, which is what she sells each t-shirt for.

The 100 that is subtracted, is the money that she spent on materials.

For eg, if she sells 8 t-shirts she makes $64, but she spent $100 before and didn't gain any profit, having not made up $36 from what her original spending was.

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Evaluate -3x3 - 4x for x = -1. 1 7 -1
soldi70 [24.7K]

The answer is -0.32.

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What is the slope of the line on the graph
Reptile [31]

Answer: y= -2x


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(-3,6)(3,-6)


M= -6-6/3-(-3)

M= -12/6

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4 0
3 years ago
The figures shows two parallel lines AB and DE cut by the transversals AE and BD::
azamat

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Consider the following predator-prey systems of differential equations dx/dt = -x/2 + xy/2 + y, dy/dt = y(1 - y) - xy/2 + y.
fgiga [73]

Answer:

a) Prey: \frac{dy}{dt}=y(1-y)-\frac{xy}{2+y}

Predator: \frac{dx}{dt}=\frac{xy}{2+y}-\frac{x}{2}

b) they grow as a function y(1-y).

c) It will grow faster and probably exponentially,

Step-by-step explanation:

a)

Prey

For prey population the rate of change is given by its own growth rate, it would be a constant times the variable, minus the rate at which it is preyed upon, usually it is represent a parameter times x and y.

So the differential equation could be:

\frac{dy}{dt}=y(1-y)-\frac{xy}{2+y}

Predator

By the other hand, the rate of change of the predator's population depends only the rate at which the predators eat preys, minus predator's intrinsic death rate.

\frac{dx}{dt}=\frac{xy}{2+y}-\frac{x}{2}

b)  If there are no predators present the differential equation that models prey population will be:

\frac{dy}{dt}=y(1-y)

So they grow as a function y(1-y).

c)  In the case of the population of prey is much grader than predator, it will grow faster and exponentially, because it we assume that preys have unlimited food supply.

I hope it helps you!

7 0
4 years ago
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