Add both distances together:
50 + 22 = 72 feet total distance.
From the first equation,
x+5 = 3(y+5)
x = 3y + 15 - 5
Now substitue x in the second equation with (3y +15 - 5).
x-5 = 7(y-5)
(3y+15-5) - 5 = 7(y-5)
3y +5 = 7y - 35
-4y = - 40
y = 10
Since y is 10, and x is (3y +15 - 5),
x = 30 + 15 - 5 = 40
Answer:
The measure of an inscribed angle is half the measure of the intercepted arc
∠EFG creates Arc EDG
if ∠EFG is 1/2 arc EDG then 115° x 2 = 230°
A circle is 360°.
The remaining arc EFG is 360° - 230° = 130°
∠EDG is 1/2 of arc EFG so, 130° ÷ 2 = 65°
∠EDG = 65°
Answer:
34/99
Step-by-step explanation:
