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murzikaleks [220]
3 years ago
8

Factoring by grouping how do i solve it 8r^3-64^2+r-8

Mathematics
1 answer:
Lelu [443]3 years ago
4 0
Squaring a number is the same as multiplying the number by itself <span>(<span><span>64⋅64</span>).</span></span><span> In this case, </span>64<span> squared is </span><span>4096.
</span><span>8<span>r^3</span>−4096+r−8

</span>Subtract 8<span> from </span><span>−4096</span><span> to get </span><span><span>−4104</span>.
</span><span>8<span>r^3</span>−4104+r

</span>Factor<span> the </span>polynomial<span> using the rational </span>roots<span> theorem.
</span><span>(r−8)(8<span>r^2</span>+64r+513)</span>
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Please help!!
postnew [5]

2  \frac{5}{8}  \div 2  \frac{1}{2}
Change the mixed fractions to improper fractions.
To do this, multiply the whole number part by the denominator. Add that to the numerator. Then write the result on top of the denominator.

You would now have:
\frac{21}{8}  \div  \frac{5}{2}
Change the division sign to a multiplication sign by turning the second fraction upside down.
That is,
\frac{21}{8}  \times  \frac{2}{5}

The answer is:
\frac{42}{40}

This can be simplified to:
\frac{21}{20}



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