Answer:
The answer is 6
Step-by-step explanation:
ABC is 72, 66, 42 and DEF is 12, 11, 7
simply divide the largest shape measurements by the smaller one.
72÷12
66÷11
42÷7
you get 6 in all of them, this technique may not work all the time.
Answer:
No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
2
in.
+
3
in.
=
5
in.
5
in.
<
6
in.
For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:
3 + 4 = 7 which is greater than 5
3 + 5 = 8 which is greater than 4
4 + 5 = 9 which is greater than 3
Step-by-step explanation:
Answer : 96
x – y = 16
--------> equation 1
x is the higher grade and y is the lower grade
We solve the first equation for y
x - y = 16
-y = 16 -x ( divide each term by -1)
y = -16 + x
Now substitute y in second equation
Take common denominator to combine fractions
Add 8 on both sides
Multiply both sides by 
x = 96
We know x is the higher grade
96 is the higher grade of Jose’s two tests.
Answer:
-2x+3
Step-by-step explanation:
Using y=mx+b
To make the line perpendicular, you just need to make the slope (m=2) negative. To make it go through (-1, 5), you just need to adjust the b value to raise the graph to a point where it will pass through the point.
Answer:
<h2>D. division property of equality</h2>
Step-by-step explanation:
