See the picture attached to better understand the problem
we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1
applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2
substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2
the answer isthe hypotenuse is (3√2)/2
Answer:
(a)
if
then
and if x<0 then 
(b)
That is straightforward from what you showed on theorem 3.25
(c)
Following the same ideas from (a) x>a or -x > a.
Step-by-step explanation:
Remember how we define the absolute value of a number.
(a)
In general

Therefore if
you have two cases, if
then
and if x<0 then 
(b)
That is straightforward from what you showed on theorem 3.25
(c)
Following the same ideas from (a) x>a or -x > a.
Answer:
I will!!!!!!
Step-by-step explanation:
ok
Answer:
Quadrangle
Step-by-step explanation:
<em>Rectangles</em> are <em>four-sided polygons</em>.
The general name for a four-sided polygon is quadrangle.
Other members of the quadrangle group are <em>squares</em> and <em>rhombuses.</em>
Answer:
Area - 6 unit^2 Perimeter - 10 units
Step-by-step explanation:
The shaded figure is 3 units long and 2 units high.
L = 3 W = 2
A = LW
A = 3 x 2 = 6 unit^2
Perimeter = 2L + 2W
P = 2(3) + 2(2)
P = 6 + 4 = 10 units