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gtnhenbr [62]
3 years ago
9

What's one fifth of 45

Mathematics
2 answers:
Gre4nikov [31]3 years ago
5 0
Well lets do the math

One way to do it is 45/5 witch would be 9.

Another way to do it is 1/5 * 45 which is also nine.

To check do 9*5 or 9+9+9+9+9 and either way you get 45.

So, one fifth of 45 in 9
pishuonlain [190]3 years ago
3 0
1 /5 = 0 . 2 
45 * . 2 = 9
Hope this helped :)
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Write the system in a matrix equation. Then, find the determinant of the matrix containing the coefficients.
Shtirlitz [24]

Answer:

See below for the matrix

D = 100

Step-by-step explanation:

\left[\begin{array}{cccc}3&2&1&-8\\-1&-2&4&7\\1&-6&-3&15\end{array}\right]

         3    2    1

D =   -1    -2    4    =   3(-2)(-3) + 2(4)(1) + 1(-1)(-6)  

         1    -6   -3

                                    - 1(-2)(1) - 3(4)(-6) - 2(-1)(-3)

                           =  18 + 8 + 6 + 2 + 72 - 6

                           =  100

Sorry, I can't type the vertical bars.

I hope this is what you are looking for.

   

5 0
3 years ago
A new Youth Sports Center is being built in Hadleyville. The perimeter of the rectangular playing field is 536  yards. The lengt
Aleksandr [31]

Answer:

W = 58 yards, L = 210 yards

Step-by-step explanation:

P = 2 (L + W)

L = 4w - 22

P = 2 (4W - 22 + W)

536 = 8W - 44 + 2W

536 = 10W - 44

10 W = 536 + 44

10W = 580

W = 58 yards

Since L = 4W - 22

L = 4 (58) - 22

L = 232 - 22

L = 210 yards

5 0
3 years ago
Please help me with this question I’m stuck going to get this right because it’s a quiz
Leno4ka [110]

Answer: True

Step-by-step explanation:

AB is congruent to RS

BC is congruent to ST

CD is congruent to TV

So DC would be congruent to VT

6 0
3 years ago
In triangle RST, m∠R > m∠S + m∠T. Which must be true of triangle RST? Check all that apply.
solmaris [256]

Answer:

1. m∠R > 90°

2. m∠S + m∠T < 90°

4. m∠R > m∠T

5. m∠R > m∠S

Step-by-step explanation:

<h3>General strategy</h3>
  1. prove the statement starting from known facts, or
  2. disprove the statement by finding a counterexample

Helpful fact:  Recall that the Triangle Sum Theorem states that m∠R + m∠S + m∠T = 180°.

<u>Option 1.  m∠R > 90°</u>

Start with m∠R > m∠S + m∠T.

Adding m∠R to both sides of the inequality...

m∠R + m∠R > m∠R + m∠S + m∠T

There are two things to note here:

  1. The left side of this inequality is 2*m∠R
  2. The right side of the inequality is exactly equal to the Triangle Sum Theorem expression

2* m∠R > 180°

Dividing both sides of the inequality by 2...

m∠R > 90°

So, the first option must be true.

<u>Option 2.  m∠S + m∠T < 90°</u>

Start with m∠R > m∠S + m∠T.

Adding (m∠S + m∠T) to both sides of the inequality...

m∠R + (m∠S + m∠T) >  m∠S + m∠T + (m∠S + m∠T)

There are two things to note here:

  1. The left side of this inequality is exactly equal to the Triangle Sum Theorem expression
  2. The right side of the inequality is 2*(m∠S+m∠T)

Substituting

180° > 2* (m∠S+m∠T)

Dividing both sides of the inequality by 2...

90° > m∠S+m∠T

So, the second option must be true.

<u>Option 3.  m∠S = m∠T</u>

Not necessarily.  While m∠S could equal m∠T, it doesn't have to.  

Example 1:  m∠S = m∠T = 10°;  By the triangle sum Theorem, m∠R = 160°, and the angles satisfy the original inequality.

Example 2:  m∠S = 15°, and m∠T = 10°;  By the triangle sum Theorem, m∠R = 155°, and the angles still satisfy the original inequality.

So, option 3 does NOT have to be true.

<u>Option 4.  m∠R > m∠T</u>

Start with the fact that ∠S is an angle of a triangle, so m∠S cannot be zero or negative, and thus m∠S > 0.

Add m∠T to both sides.

(m∠S) + m∠T > (0) + m∠T

m∠S + m∠T > m∠T

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠T.

So, option 4 must be true.

<u>Option 5.  m∠R > m∠S</u>

Start with the fact that ∠T is an angle of a triangle, so m∠T cannot be zero or negative, and thus m∠T > 0.

Add m∠S to both sides.

m∠S + (m∠T) > m∠S + (0)

m∠S + m∠T > m∠S

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠S.

So, option 5 must be true.

<u>Option 6.  m∠S > m∠T</u>

Not necessarily.  While m∠S could be greater than m∠T, it doesn't have to be.  (See examples 1 and 2 from option 3.)

So, option 6 does NOT have to be true.

4 0
1 year ago
Find the difference. express your answer in simplest form. (2s/s^2-4s+4) - (4/s^2-4s+4)
LUCKY_DIMON [66]
To find the difference, we are going to destroy the parenthesis first, and then, we are going to perform the operations. Remember that to destroy a parenthesis preceded by a negative sign (-), you should change the signs of the factors inside the parenthesis:
\frac{2s}{s^2-4s+4} -( \frac{4}{s^2-4s+4} )
\frac{2s}{s^2-4s+4} -\frac{4}{s^2-4s+4}= \frac{2s-4}{s^2-4s+4}

Now we can factor both numerator and denominator and simplify:
\frac{2s-4}{s^2-4s+4} = \frac{2(s-2)}{(s-2)^2} = \frac{2}{s-2}

We can conclude that the difference in simplest form is: \frac{2}{s-2}
5 0
3 years ago
Read 2 more answers
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