All categories

3 years ago

Factorise the following expression using grouping and use binomial products to simplify.

Mathematics

2 answers:

Blizzard [7]3 years ago

7 0

Answer:

Answer is below. I have grouped it.

Step-by-step explanation:

=(11x-55) + (-5a+ax)

=11 ( x - 5) +a ( -5+x)

= 11(x-5)+a(x-5)

(11+a)(x-5)

(x-5)(11+a)

rewona [7]3 years ago

6 0

Answer:

11x-55-5a+ax

11(x-5)+a(x-5)

(11+a)(x-5)

Step-by-step explanation:

First you factor out the common factors

for(11x-55) is would be 11 as both of these figures are the multiple of 11

for(ax-5a) the common factor is a which will be factor out

Then after doing the process you will get

11(x-5)+a(x-5)

then factor out(x-5)which will give you

(11+a)(x-5)

You might be interested in

Someone please help

Lelechka [254]

Answer:

Im sorry im not sure how to do this either lol :/

Step-by-step explanation:

8 0

3 years ago

Alonzo is saving money to buy a game. So far he has saved $30 , which is two-thirds of the total cost of the game. How much does

Andrei [34K]

Well, it should be 45 because 1/3 of the game would be 15 and 15+15 is 30 (2/3rds cost), so 15+15+15, 45, would be the full cost of the game

7 0

3 years ago

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0

3 years ago

Can someone please help me with number 2?I don't know what I did wrong.

Dmitry [639]

Part A

Let's say point P is the starting point and point Q is the endpoint

x = one-way distance from P to Q, and vice versa

The goal is to find x, then compute 2x to find the round trip distance traveled.

We'll use this idea

distance = rate*time

which solves to

time = distance/rate

So when going from P to Q, the driver is going 70 mph and travels x miles

So the driver does this for distance/time = x/70 hours.

When going back, the driver slows down to 55 mph so the time taken here is x/55 hours.

The total time values add to x/70 + x/55 hours

Set this equal to the total driving time of 7 hours and solve for x

x/70 + x/55 = 7

70*55*(x/70 + x/55) = 70*55*7

70*55*(x/70) + 70*55*(x/55) = 26,950

55x + 70x = 26,950

125x = 26,950

x = (26,950)/125

x = 215.6 which is the one-way distance in miles

which then means,

2x = 2*215.6 = 431.2

Therefore, the total distance traveled is 431.2 miles

<h3>Answer: 431.2 miles</h3>

=========================================================

Part B

To find the duration of each trip, we simply need to evaluate x/70 and x/55. Those are the durations when going 70 mph and 55 mph respectively. These durations are measured in hours.

x/70 = (215.6)/70 = 3.08

x/55 = (215.6)/55 = 3.92

Note how 3.08+3.92 = 7 to help verify the answers.

<h3>Answers:</h3>

When going 70 mph, it takes about 3.08 hours
When going 55 mph, it takes about 3.92 hours

6 0

2 years ago

If Measure of angle a is 155°, what is Measure of angle c?

dybincka [34]

Answer:

C is the answer

Step-by-step explanation:

pls add me on brainlist

7 0

3 years ago

Read 2 more answers