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posledela
3 years ago
12

Need the answers please

Mathematics
1 answer:
lakkis [162]3 years ago
8 0

Answer:

⁸

⅔

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Part 3 <br>please help <br>​
aleksandr82 [10.1K]

I'm taking "part 3" to mean the 3rd of the posted questions.

If f(x)=(x^3+2x)\ln x, then

f'(x)=(x^3+2x)'\ln x+(x^3+2x)(\ln x)'=(3x^2+2)\ln x+\dfrac{x^3+2x}x

\implies f'(x)=(3x^2+2)\ln x+x^2+2

Then when x=1, we get f'(1)=3.

6 0
3 years ago
Wallace took out a $5,000 loan for six years. He is being charged 4 percent interest, compounded annually. Calculate the total a
Korolek [52]
The solution is 6326.59509248 =6329.60

p=5000,r=4,t=6 years

compound interest=P[1+r\100]^(t)
8 0
3 years ago
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What are the solutions to the following system of equations? y=x^2+12x+30 and 8x-y=10
Ierofanga [76]
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:

8x-10 = x^2+12x+30

Group all terms together on the right side.  To do this, add -8x+10 to both sides.  Then 0 = x^2 +4x +40.  You must now solve this quadratic equation for x, if possible.  I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.

If you have a graphing calculator, please graph 8x-10  and  x^2+12x+30 on the same screen.  You will see two separate graphs that do NOT intersect.  This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
6 0
4 years ago
Write the equation: Five times the difference of a number and six is twenty.​
xz_007 [3.2K]

Answer:

C. 5(x-6)=20

Step-by-step explanation:

we can represent the value of x decreased by 6 times 5 as 5(x-6) and then show that that is equal to 20.

4 0
3 years ago
Read 2 more answers
What adds to be 10 and multiplies to be 24
svet-max [94.6K]
Let x and y be the 2 numbers

x + y = 10
x*y = 24
------------

4 and 6
6 0
4 years ago
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