I'm taking "part 3" to mean the 3rd of the posted questions.
If
, then


Then when
, we get
.
The solution is 6326.59509248 =6329.60
p=5000,r=4,t=6 years
compound interest=P[1+r\100]^(t)
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
Answer:
C. 5(x-6)=20
Step-by-step explanation:
we can represent the value of x decreased by 6 times 5 as 5(x-6) and then show that that is equal to 20.
Let x and y be the 2 numbers
x + y = 10
x*y = 24
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4 and 6