Answer:
1.
x=-10
x=-6
2.
x=10
x=-3
Step-by-step explanation:
to find the zeros of a function you need to set it equal to zero:
x^2+16x+60=0
then you factor
(x+10)(x+6)=0
then you have to finish factoring/simplifying
x+10=0
-10
x=-10
x+6=0
-6
x=-6
and the same thing for number 2
x^2-7x-30=0
(x-10)(x-3)=0
x=10, x=3
Answer:

So then the best answer for this case would be:
C. 2.78
Step-by-step explanation:
For this case we have the following probabability distribution function given:
Score P(X)
A= 4.0 0.2
B= 3.0 0.5
C= 2.0 0.2
D= 1.0 0.08
F= 0.0 0.02
______________
Total 1.00
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
If we use the definition of expected value given by:

And if we replace the values that we have we got:

So then the best answer for this case would be:
C. 2.78
Answer:
p+q = 38/15
Step-by-step explanation:
2/3+p = 1. p = 1 - 2/3
4/5 + q = 3. q = 3 - 4/5
p + q = 1 - 2/3 + 3 - 4/5
-2/3 - 4/5 (common denominator = 15)
4 - 10/15 - 12/15 = 4 - 22/15
4 - 22/15 = (4*15 - 22)/15
= 38/15
Answer:
( x - 3 )( x + 3 ) ( x - 4 )( x + 4)
Step-by-step explanation:
( x^2 - 9 ) ( x^2 - 16 )
( x - 3 )( x + 3 ) ( x - 4 )( x + 4)
Hopefully this helps!
Brainliest please?