Hi There! :)
Jay, Kay, and Ray found themselves far apart when they stopped for lunch while walking in a field. Jay could see Kay, then turn through 75th, and couldsee Ray. Jay could see Ray, then turn through 50th amd see Jay. Ray could see Jay, the turn through 55th, and see Kay. Which two were the farthest apart?
A. Kay and Ray
B. Jay and Kay
C. Ray and Jay
D. Kay and Ray were the same distance apart as Ray and Jay
I believe it's <span>A. Kay and Ray</span>
Answer:
<u>Solved for y:</u> 
<u>Solved for x:</u> 
Step-by-step explanation:
Solving for y
<u>Step 1: Subtract 5x from both sides</u>
<u>Step 2: Divide both sides by -6</u>
Solving for x
<u>Step 3: Add 6y to both sides</u>
<u>Step 4: Divide both sides by 5</u>
Therefore the answer is √18
There are 2 orange marbles, 3 green marbles, & 5 purple marbles
two consecutives draws <em>without</em> replacement
Orange first, green second
Orange/total = 2/10, or 1/5
green/total - 1 = 3/9, or 1/3
1/5(1/3) = 1/15
There is a 1/15 chance of <em>Orange first, green second</em>
Both marbles are purple
Purple/total = 5/10, or 1/2
Purple/total = 4/9, or <em>44% chance of both being purple</em>
first is purple, the next is anything but purple
purple/total = 1/2, or 50% chance
(everything - purple)/total = 5/10, or 50% chance
1/2(1/2) = 1/4, or 25% chance of <em>first purple, then anything but purple</em>
hope this helps
The relation is not a function because the value 3 in the domain is paired with two different values in the range.
Good luck!!!
