Answer: B. 461 acres
Step-by-step explanation:
Given : In an agricultural study, the average amount of corn yield is normally distributed with a mean of 185.2 bushels of corn per acre, with a standard deviation of 23.5 bushels of corn.
i.e. 
Let x denotes the amount of corn yield.
Now, the probability that the amount of corn yield is more than 190 bushels of corn per acre.

[Formula :
]
[∵ P(Z>z)=1-P(Z<z)]
[using z-value calculator or table]

Now, If a study included 1100 acres then the expected number to yield more than 190 bushels of corn per acre :-

hence, the correct answer is B. 461 acres .
Answer:
I think it's A because.
Step-by-step explanation:
A trendline is a line drawn over pivot highs or under pivot lows to show the prevailing direction of price. Trendlines are a visual representation of support and resistance in any time frame. They show direction and speed of price, and also describe patterns during periods of price contraction.
Answer:
1.06 × 5(r-4) = 45.05
Step-by-step explanation:
Let r represents the regular price of each T-shirt,
After getting $ 4 off in regular price,
New price of each T-shirt = r - 4,
Thus, new price of 5 T-shirts = 5 × price of each T-shirt
= 5(r - 4)
Since, there is 6% sales tax,
Then, the final price after discount = 5(r - 4) + 6% of (5(r-4))
= 5(r-4) + 0.06(5(r-4))
= 1.06 × 5(r-4)
According to the question,
1.06 × 5(r-4) = 45.05
Which is the required equation.
I Lou think the answer is 84?
Answer:
B. - Three T-Shirts and Seven Sweatshirts: $37.5 + $203 =<u>240.50 </u>
- Six T-Shirts and Five Sweatshirts: $75 + $145 = <u>$220</u>
Step-by-step explanation:
A. - Three T-Shirts and Seven Sweatshirts: $27 + $213.50 = <u>$240.50</u>
- Six T-Shirts and Five Sweatshirts: $54 + $152.5 = <u>$206.5</u>
B. - Three T-Shirts and Seven Sweatshirts: $37.5 + $203 =<u>240.50 </u>
- Six T-Shirts and Five Sweatshirts: $75 + $145 = <u>$220</u>
C. - Three T-Shirts and Seven Sweatshirts: $35.01 + $210 = <u>$245.01</u>
- Six T-Shirts and Five Sweatshirts: $70.02 + $150 = <u>$220.02</u>
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<u>Mark as Branliest Please! :)</u>