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Nookie1986 [14]
3 years ago
7

Sorry again I just dont know this.

Mathematics
1 answer:
natta225 [31]3 years ago
4 0

Answer:

7 ; 2 ; 8

Step-by-step explanation:

money for raffle= 350 pounds

money for quiz=14 multiplied by 4= 56

56+44= 100

money for membership fees= 20 multiplied by 20= 400

Ratio

Raffle :Quiz: Membership fees

350 : 100 : 400

35 : 10 : 40 (divided by 10)

7 : 2 : 8        (divided by 5)

it can not be simplified further

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There is a mound of g pounds of gravel in a quarry. Throughout the day, 300 pounds of gravel are added to the mound. Two orders
galina1969 [7]

Answer:

g+300-700-700=1500, g=2600

Step-by-step explanation:

At the start of the day there are g pounds of gravel in the quarry.

Then it says that there were 300 pounds added to the mound, so at this point the pounds of gravel in the mound are now g+300.

Then two orders of 700 pounds are sold and removed from the mound. That means they removed 700 pounds from the mound 2 times. Therefore at this point the pounds of gravel in the mound are now g+300-700-700.

Then it says that at this point, the amount of pounds in the mound are 1500.  Hence we get

g+300-700-700=1500

To solve for g we just add 700 two times to both sides of the equation, and subtract 300 from both sides of the equation, getting:

g+300-700-700+700+700-300=1500+700+700-300

And so g=2600

4 0
3 years ago
What is the slope of (2,5) and (5,8)
murzikaleks [220]

Answer:

Slope = 1

Step-by-step explanation:

Slope = change in y/change in x

         = (8-5)/(5-2)

        =3/3

6 0
3 years ago
Please help this is due in tomorrow!!
Nataly_w [17]

Answer:it would be 15cm^2 I think

Step-by-step explanation:

7 0
3 years ago
Sammy has 4 bags of marbles. Each bag has 12 marbles in it. Which equation represents how many total marbles he has
kumpel [21]

Answer:

t = 4 x 12

Step-by-step explanation:

t = total # of marbles

Equation: t = 4 x 12

=48

4 0
2 years ago
Read 2 more answers
Hey Mahfia, please help! Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at
Dafna1 [17]

Answer:

\huge\boxed{  \red{ \boxed{ \tt{ \frac{ {y}^{2} }{ {10}^{2} }  -  \frac{ {x}^{2} }{ {12}^{2} }  = 1}}}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • conic sections
  • PEMDAS
<h3>tips and formulas:</h3>
  • \sf hyperbola \:equation :  \\  \sf  \frac{ {x}^{2} }{ {a}^{2} }   -  \frac{ {y}^{2} }{ {b}^{2} }  = 1
  • vertices of hyperbola:(±a,0) and (0,±b) if reversed
  • \sf \: asymptotes :  \\ y =   \pm\frac{b}{a} x
<h3>given:</h3>
  • vertices: (0,±10)
  • the hyperbola equation is inversed since the vertices is (0,±10)
  • asymptotes:\pm \frac{5}{6}x
<h3>let's solve:</h3>
  • the asymptotes are in simplest and we know b is ±10

according to the question

  1. y =  \sf  \frac{5 \times 2}{6 \times 2} x \\ y =  \frac{10}{12} x

therefore we got

  • a=12
  • b=10

note: the equation will be inversed

let's create the equation:

  1. \sf substitute \: the \: value \: of \: a \: and \: b :  \\  \sf  \frac{ {y}^{2} }{ {10}^{2} }  -  \frac{ {x}^{2} }{ {12}^{2} }  = 1

3 0
3 years ago
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