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lyudmila [28]
3 years ago
6

please help me, a point thief gave a me a silly fake answer the first time, now no one will answer me. Write the given equation

in slope-intercept form, y = mx + b, by solving for y. 4x – 2y = 10 y = 2x – 5 y = -4x – 5 y = 2x + 5 y = -2x – 5
Mathematics
2 answers:
vaieri [72.5K]3 years ago
3 0
4x - 2y = 10
-2y = -4x + 10
y = 4/2x - 10/2
y = 2x - 5 <==
Elenna [48]3 years ago
3 0
4x - 2y = 10

-2y = -4x + 10

y   = -4x /-2 + 10/-2

y = 2x - 5
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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
barxatty [35]

Step-by-step explanation:

I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.

y = -16x² + 64x + 89

shows us that the tower is 89 ft tall (the result for x = 0, at the start).

anyway, if the original assumption is correct, then we need to solve

0 = -16x² + 64x + 89

the general solution for such a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/)2a)

in our case

a = -16

b = 64

c = 89

x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =

= (-64 ± sqrt(4096 + 5696))/-32 =

= (-64 ± sqrt(9792))/-32

x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s

x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s

the negative solution for time is but useful here (it would be the time calculated back to ground at the start).

so, x2 is our solution.

the rocket hits the ground after about 5.09 seconds.

5 0
2 years ago
Evaluate the expression described below if the number is 4.
Archy [21]
<em>x</em>² - x

<em>x</em> = 4

4² - 4 

16 - 4 = 12

Hope this helps!
5 0
4 years ago
PLEASE HELP ASAP! THANK YOU
Dafna1 [17]

Answer:

39 m.

Step-by-step explanation:

The area of a triangle is calculated by the expression given as:

Area = bh/2

where b is the base and h is the height.

We calculate as follows:

270 = b (15) / 2

b = 36

hypotenuse = sqrt ( 15^2 + 36^2 ) = 39

4 0
3 years ago
Changle. Show all work. Round each length to the nearest tenth and each angle to the
Sedaia [141]

Answer:

Part 1) BC=12.2\ units

Part 2) m\angle A=55^o

Part 3) m\angle C=35^o

Step-by-step explanation:

Part 1) Find AC

we know that

In the right triangle ABC of the figure

Applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

AC^2=7^2+10^2

AC^2=149\\AC=12.2\ units

Part 2) Find the measure of angle A

we know that

In the right triangle ABC

tan(A)=\frac{BC}{AB} ----> by TOA (opposite side divided by the adjacent side)

substitute the values

tan(A)=\frac{10}{7}

using a calculator

m\angle A=tan^{-1}(\frac{10}{7})=55^o

Part 3) Find the measure of angle C

we know that

In the right triangle ABC

m\angle A+m\angle C=90^o ----> by complementary angles

substitute the given value

55^o+m\angle C=90^o

m\angle C=90^o-55^o=35^o

8 0
3 years ago
Please please help! I will mark you brainliest thank you math experts
TEA [102]

Answer:

Right skewed Histogram.

Explanation:

As the peak of the graph lies to the left side of the centre.

6 0
3 years ago
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