Answer:
none of the above
f(x) ≈ 197·1.03^x; approximately 3% daily
Step-by-step explanation:
If we let x represent days, then x/7 represents weeks and we can rewrite f(x) as ...
f(x/7) = 197·1.25^(x/7) = 197·(1.25^(1/7))^x
f(x) ≈ 197·1.03^x
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The daily multiplier of 1.03 represents a daily growth rate of
1.03 -1 = .03 = 3%
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These answers are not found among the offered choices:
f(x) = 197·1.03^x
3% daily growth
Step-by-step explanation:
Answer:
46
Step-by-step explanation:
14-60 equals 46 and just go to your answer and put that in and there u go buddy
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
- a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°
- b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
- c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,
Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
- d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment
Answer:
The domain represents a 12-month period of flower production
Step-by-step explanation:
The <em>domain</em> is <em>the horizontal extent of the graph</em>. Both the problem statement and the graph itself tell you that is a 12 month time period.
Answer:
see the explanation
Step-by-step explanation:
we know that
<u><em>Alternate Exterior Angles</em></u> are created where a transversal crosses two lines. Notice that the two alternate exterior angles are equal in measure if the two lines are parallel
In this problem
----> by alternate exterior angles
One way to verify alternate exterior angles is to see that they are the vertical angles of the alternate interior angles