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3 years ago

9

Triangle A″B″C″ is formed by a reflection over y = −3 and dilation by a scale factor of 2 from the origin. Which equation shows

the correct relationship between ΔABC and ΔA″B″C″

2 answers:

TiliK225 [7]3 years ago

6 0

Answer:

The correct answer is C if the answers are the same as the picture attached.

nekit [7.7K]3 years ago

6 0

Answer:

The correct answer is C.

Step-by-step explanation:

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Point N is on line segment MO. Given NO=2x−3, MO=3x+5, and MN=2x+3, determine the numerical length of MO.

ELEN [110]

Answer:-19

Step-by-step explanation:

3x+5-(2x-3)=0

3x+5-2x+3=0

x+8=0

x=-8

substitute x into 3x+5 to find the length of MO

3x+5

3(-8)+5

-24+5

-19

6 0

3 years ago

Which number sentence below is not correct?

Mama L [17]

17.154 < 17.15 is incorrect.
17.15 is 17.150 which is less than 17.154 not greater than.

6 0

3 years ago

Rico spent $87.00 to go to the movies on Friday night. He spent $25.75 on popcorn and drinks and paid $12.25 for each movie tick

Svetlanka [38]

You haven't given the equations I'm supposed to chose from, but the answer would be

25.72 + 12.25x = 87.00 is the equation.

He spent a total of $87

The popcorn was 25.75 and each ticket was 12.25, which means we must add the amounts they costs and multiply how my tickets he bought, which is x.

5 is the solution

7 0

3 years ago

Read 2 more answers

Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0

marin [14]

If you do in fact mean $f(1)=f(6)=0$ (as opposed to one of these being the derivative of $f$ at some point), then integrating twice gives

$f''(x) = -\dfrac1{x^2}$

$f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1$

$f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2$

From the initial conditions, we find

$f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0$

$f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)$

Eliminating $C_2$ , we get

$(C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))$

$-5C_1 = \ln(6)$

$C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)$

Then

$\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}$

3 0

2 years ago

B(7, 2) and C(-1,-9) are the endpoints of a line segment. What is the midpoint M of that line

Oksana_A [137]

Answer:

(3,-3.5)

Step-by-step explanation:

$Mid-point formula : \frac{ x_{1} +x_{2}} {2}, \frac{y_{1}+y_{2} }{2} \\\\x=\frac{7+(-1)}{2} , y= \frac{2+(-9)}{2} \\x= \frac{6}{2} , y= \frac{-7}{2} \\x=3 , y= -3.5$

Midpoint M of the line segment is (3,-3.5)

4 0

3 years ago