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3 years ago

How do you solve #6?

Mathematics

1 answer:

velikii [3]3 years ago

7 0

You seem to already see that you need to multiple x with the other numbers. When you start off solving it you'd get.. x-6=x2(to the power of) + 6x . Then just move the equation over from the left to the right. and solve, I've got -6+x2(power of 2)+7x, that's it

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The length of a rectangular garden is 6 more than its width. If the perimeter is 32 feet, what is the width and the area of the

PolarNik [594]

Answer:

${\fbox{ \sf{Width \: of \: a \: rectangular \: garden \: = 5 \: feet}}}$

$\boxed{ \sf{ \: Area \: of \: a \: rectangular \: garden = 55 {ft}^{2}}}$

Step-by-step explanation:

$\star$ Let the width of a rectangular garden be 'w'

$\star$ Length of a rectangular garden = 6 + w

$\star$ Perimeter of a rectangular garden = 32 feet

 $\longrightarrow$ Finding the width of a rectangular garden :

$\boxed{ \sf{ \: Perimeter \: of \: a \: rectangle \: = \: 2(length + width}}$

$\mapsto{ \text{32 = 2(6 + w + w)}}$

$\text{Step \: 1 \: : Collect \: like \: terms}$

Like terms are those which have the same base

$\mapsto{ \text{32 = 2(6 + 2w) }}$

$\text{Step \: 2 \: : Distribute \: 2 \: through \: the \: parentheses}$

$\mapsto{ \text{32 = 12 + 4w}}$

$\text{Step \: 3 \: : Swap \: the \: sides \: of \: the \: equation}$

$\mapsto{ \text{4w + 12 = 32}}$

$\text{Step \: 4 \: : Move \: 12 \: to \: right \: hand \: side \: and \: change \: its \: sign}$

$\mapsto{ \text{4w = 32 - 12}}$

$\text{Step \: 5 \: : Subtract \: 12 \: from \: 32}$

$\mapsto{ \sf{4w = 20}}$

$\text{Step \: 6 \: : Divide \: both \: sides \: by \: 4}$

$\mapsto{ \sf{ \frac{4w}{4} = \frac{20}{4}}}$

$\text{Step \: 7 \: : Calculate}$

$\mapsto{ \text{w = 5}}$

Width of a rectangular garden = 5 feet

$\longrightarrow$ Substituting / Replacing the value of w in 6 + w in order to find the length of a rectangular garden

$\mapsto{ \sf{Length = 6 + w = 6 + 5 = \bold{11 \: feet} }}$

$\longrightarrow$ Finding the area of a rectangular garden having length of 11 feet and width of 5 feet :

$\boxed{ \sf{Area \: of \: a \: rectangle = length \:∗ \: width}}$

$\mapsto{ \text{Area \: = \: 11 \: ∗ \: 5}}$

$\mapsto{ \sf{Area \: = 55 \: {ft}^{2} }}$

Area of a rectangular garden = 55 ft²

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

6 0

3 years ago

A soup bowl is in the shape of a hemisphere with a diameter of 10 cm. What is the approximate maximum volume of soup that the bo

Oduvanchick [21]

Answer:

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Step-by-step explanation:

The maximum water that bowl can hold = The volume of the bowl

$\boxed{ \mathsf{volume \: of \: bowl = \frac{2}{3} \times \pi \: r {}^{3} }}$

Radius is half of diameter.

Given -

Diameter = 10cm .

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Putting the known values into the formula to get the value of the volume of bowl :

$\mathsf{volume = \frac{2}{3} \times \: 3.14 \: \times {5}^{3} }$

= 3.48888cm³

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kozerog [31]

Answer:

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Step-by-step explanation:

................

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