Answer:
Logistic, a limiting value of 29,864
Step-by-step explanation:
Did the assignment
The area of a rhombus is the product of the diagonals divided by 2. In this question, the diagonals are given, so that's really easy. Let's convert the measures to meters, that'll help for the final area calculation:
Area of one rhombus: (0.52x0.30)/2 = 0.078 m²
In 60 m², you can fit 60/0.078 tiles. That's 769.23, rounded to 770 since you'll have to cut up the last tile.
Equation for perimeter is 2L +2W
perimeter of the lot is 390 ft
so we have 390 = 2L +2w
divide all terms by 2:
195 = L + W
rewrite this as L = 195-W ( eq.1)
cost of fence for the length = 36 per foot so we have 36L
cost of fence for width = 6 per foot so we have 6W
the fence was 1 length and 2 sides
so we have 36l + 6w +6w = total cost
total cost is 4980
so we have 4980 = 36L + 6w +6w
combine like terms:
4980 = 36L +12w
replace L with eq1 from above:
4980 = 36(195-w) +12w
distribute:
4980 = 7020 -36w +12w
combine like terms:
4980 = 7020-24w
subtract 7020 from both sides:
-2040 = -24w
divide both sides by -24:
-2040 / -24 = 85
width = 85 feet
using eq1 L = 195 - 85
Length = 110 feet
lond = 110 feet
short = 85 feet
