The inscribed circle has its center at the point of intersection of the angle bisectors, which also happen to be the medians. Hence the altitude of the triangle is 3 times the radius, or 12 inches.
The side length of this triangle is 2/√3 times the altitude, so the area is
... Area = (1/2)·b·h = (1/2)·(24/√3 in)·(12 in)
... Area = 48√3 in² ≈ 83.1384 in²
Answer:
Shown
Step-by-step explanation:
Given that twelve basketball players, whose uniforms are numbered 1 through 12, stand around the center ring on the court in an arbitrary arrangement.
Let us consider consecutive numbers in this set.
After this we find the totals are more than 20.
When 1 to 12 are arbitrarily arranged, there are chances that numbers from 6 and above are having consecutive numbers.
These totals are greater than 20
Hence shown that some three consecutive players have the sum of their numbers at least 20.
(i.e. starting from if we take)