Question

Please show all work with the answers please

Answer 1

Part A

The angle of elevation of the staire case is given by

$Angle\ of\ elevation=\tan^{-1}{ \frac{Vertical\ rise}{landing} } \\ \\ =\tan^{-1}{ \frac{14}{20} }\approx35^o$



Part B:

If the landing of each step is changed to 17 inches and the elevation of each step to 21 inches, the new angle of elevation for the staircase is given by

$Angle\ of\ elevation=\tan^{-1}{ \frac{Vertical\ rise}{landing} } \\ \\ =\tan^{-1}{ \frac{17}{21} }\approx39^o$