To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,
Therefore, 500 gallons of 80% antifreeze solution is required.
A= bh(1/2)
a=12(14)(1/2)
a= 168(1/2)
a= 84inches
━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━
If Ali has x cards, then Belinda has 2x cards.
If Ali has x cards, then Charlie has x+5 cards.
2x (Belinda) + x+5 (Charlie) + x (Ali) = 33 (total)
2x + x+5 + x = 33
Now simplify the equation... x+x+5 can be simplified as 2x+5.
2x+5 plus 2x can become 4x+5.
So their total number is 4x+5.
So 4x+5=33.
You want to isolate the variables and numbers.
To remove the 5 from the left side, subtract 5 from both sides.
4x+5-5=4x - 33-5=28
So the equation now is 4x=28
To remove the 4, divide each side by 4.
4x÷4=x - 28÷4=7
So x equals 7, Ali has 7 cards.
━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━
