A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

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7 0

1 year ago

What is 5x + 12 < 2 ?

Masja [62]

Answer:

x < -2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify.

5x + 12 < 2

Step 2: Solve for x

[Subtraction Property of Equality] Subtract 12 on both sides: 5x < -10
[Division Property of Equality] Divide 5 on both sides: x < -2

5 0

2 years ago

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