Question

Please help urgent!!

Answer 1

Answer:

The area of the rectangle is $A=12b^6+6b^3-18b^2$

Step-by-step explanation:

Area of a rectangle

A rectangle of height H and width W has an area of:

$A=H*W$

The rectangle shown in the figure has a height of:

$H=3b^2$

And a width of

$W=4b^4+2b-6$

The area is

$A=(3b^2)(4b^4+2b-6)$

Operating:

$A=(3b^2)*4b^4+(3b^2)*2b-(3b^2)6$

$A=12b^6+6b^3-18b^2$

The area of the rectangle is $A=12b^6+6b^3-18b^2$