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GREYUIT [131]
3 years ago
8

At the calendar shop, wall calendars cost $8 and desk calendars cost $10. Steve spent $42 to buy 5 calendars. How many of each t

ype of calendar did Steve buy?
______ Wall Calendar

______ Desk Calender
Mathematics
2 answers:
alexira [117]3 years ago
6 0
4 wall calendars and 1 desk calendar
kodGreya [7K]3 years ago
3 0
He bought 4 wall calendars and 1 desk calendars

Because 4 X 8 = 32
And 1 x 10 = 10

32 + 10 = 42
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Good luck everyone if this is your last bit of school. :)
salantis [7]

Answer:

Thnx Bro

U to

Step-by-step explanation:

8 0
2 years ago
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A stone is thrown horizontally with an initial speed of 8 m/s from the edge of a cliff. a stop watch measures the stone's trajec
Tamiku [17]

Answer:

90.6m

Step-by-step explanation:

Initial speed = 8m/s

Time = 4.3 s

In studying the motion of an object, we often make use of kinematic equation

s = ut + 1/2at^2

v^2 = u^2 + 2as

a = (v - u) / t

v = final velocity

u = initial velocity

s = distance or height

t = time

a = acceleration due to gravity

Given time to hit the ground as 4.3s, we calculate the height by using

s = ut + 1/2at^2

Since the stone is moving against gravity, a is negative

u = 0

s = 0(4.3) +1/2(-9.8)(4.3)^2

s = -90.6m

The height of the cliff is 90.6m

7 0
2 years ago
What is the probability of rolling a 4 on a number cube and flipping tails on a coin?
kakasveta [241]
1. 1/6

2. 1/2
This is the correct answer
3 0
2 years ago
Read 2 more answers
Gauss-Jordan Elimination
kogti [31]

(Correct answer choices in boldface)

The total of the three payments comes out to $29000, so

x+y+z=29000

"Two times the first installment is $1000 more than the sum of the third installment and three times the second installment" translates to

2x=1000+z+3y\implies2x-3y-z=1000

The second and third installments have a 15% interest rate, but there's no interest on the first installment. The total interest owed is $2100, so

0.15y+0.15z=2100

In augmented matrix form, this system is equivalent to

\begin{bmatrix}1&1&1&29000\\2&-3&-1&1000\\0&0.15&0.15&2100\end{bmatrix}

### Row 2, column 1 ### (not row 1, column 1)

The third equation is equivalent to

\dfrac1{0.15}(0.15y+0.15z)=\dfrac{2100}{0.15}\iff y+z=14000

so the third row in the matrix could adjusted to get

\begin{bmatrix}1&1&1&29000\\2&-3&-1&1000\\0&1&1&14000\end{bmatrix}

Also, adding the first row to the second gives

\begin{bmatrix}1&1&1&29000\\3&-2&0&30000\\0&1&1&14000\end{bmatrix}

### Row 3, column 2 ### (not row 1, column 2)

Subtracting row 3 from row 1 gives

\begin{bmatrix}1&0&0&15000\\3&-2&0&30000\\0&1&1&14000\end{bmatrix}

Subtracting 3 times row 1 from row 2 gives

\begin{bmatrix}1&0&0&15000\\0&-2&0&-15000\\0&1&1&14000\end{bmatrix}

and multiplying row 2 by -1/2 gives

\begin{bmatrix}1&0&0&15000\\0&1&0&7500\\0&1&1&14000\end{bmatrix}

Finally, subtracting row 2 from row 3 gives

\begin{bmatrix}1&0&0&15000\\0&1&0&7500\\0&0&1&6500\end{bmatrix}

### Row 2, column 3 ### (not row 3, column 2)

5 0
3 years ago
The sum of two numbers is 20. The difference between three times the first number and twice the second is 40. Find the two numbe
KiRa [710]
Their sum can be written as : a+b=20. this means that b=20-a

and the phrase: The difference between three times the first number and twice the second is 40 like this:

3a-2b=40

and we can substitute:
3a-2b=40
 3a-2(20-a)=40
 3a-40+2a=40

5a=40+40
5a=80

a=16
so b must be 4!

let's check:

3*16-2*4=48-8=40 correct!



4 0
2 years ago
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