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kozerog [31]
3 years ago
5

a right triangle is rotated a round a line that includes one of the legs of the triangle. What figure is located?

Mathematics
1 answer:
Crank3 years ago
5 0

Answer: Its a cone

Explanation:

When a right angle triangle is rotated about any of its leg a cone is formed.

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10. Mr. Guerrero left his house and drove north at an average speed of 40 mph.Two hours later, his daughter Miranda left the hou
Charra [1.4K]
Speed=distance / time  ⇒ distance=time x speed
distance=d
time=t
speed= s

d=s*t

Distance  traveled by Mr Guerrero, when his daugther left the house
Data:
s=40 miles/ hour
t=2 hours
d=40 miles/ hour * 2 hours=  80 miles

Total distance traveled by Mr Guerrero:
d=80 miles + 40 miles/hourt    ⇒d=80+40t      (1)

d=total distance.
s=speed.
t=time spent by Miranda for she overtook her father.

Distance traveled by Miranda.
data:

s=48 miles/ hour
d=total distance.
t=time spent by Miranda for she overtook her father.

d=48 miles/hour * t      ⇒d=48t       (2)

With the equations (1) and (2), we make an system of equations:

d=80+40t
d=48t

We can solve this system of equation by equalization method.

80+40t=48t
80=48t-40t
80=8t
t=80/8=10

d=48t
d=48*10=480

Answer: the thistance will be 480 miles.
3 0
3 years ago
Last Wednesday, students could choose ham or turkey sandwiches for lunch. The cafeteria made 75 sandwiches in all, 51 of which w
exis [7]

Answer:

0.68%

Step-by-step explanation:

7 0
2 years ago
HELP PLS QUICK MIGHT GIVE BRAINLIST ONLY IF 2 PEOPLE ANSWER!
Afina-wow [57]

Answer:

area = 10 squares units

if points changes

5 0
3 years ago
4xi + 5yi^8+ 6xi^3 + 2yi^4
Ad libitum [116K]

Answer:

The correct answer is,

7y - 2ix

5 0
3 years ago
How to factor 6n2 - 6n - 12
alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

6n^2-6n-12 = 6(n^2-n-2)

We can set this equal to 0 and factor by using the quadratic formula which is:

x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

So, let's do just that:

6(n^2-n-2) = 0

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}

\frac{-1 \pm \sqrt{9} }{2} = {1, -2}

So, we can write this as:

6n^2 - 6n - 12 = 6(n-1)(n+2)

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

7 0
3 years ago
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