Answer:
is easyy just go multiply
Step-by-step explanation:
Numbers are:
2x+1, 2x+3, 2x+45
Sum:
2x+1+2x+3+2x+5=111
6x=111-9
6x=102
x=17
Smaller = 2x+1 = 35
Given:
Consider the given equation is

To find:
The missing value in the given equation and complete the equation.
Solution:
We have,

Taking LHS, we get

![[\because a^ma^n=a^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5Ema%5En%3Da%5E%7Bm%2Bn%7D%5D)

and,

Let the missing value be k.
For each equation LHS=RHS.


Therefore, the missing value is 10 and the complete equation is
.