Answer:
f = 1, w = 4
Step-by-step explanation:
Given the 2 equations
5w = 23 - 3f → (1)
4f = 12 - 2w (add 2w to both sides )
2w + 4f = 12 ( subtract 4f from both sides )
2w = 12 - 4f → (2)
Multiplying (1) by 4 and (2) by - 3 and adding the result will eliminate f
20w = 92 - 12f → (3)
- 6w = - 36 + 12f → (4)
Add (3) and (4) term by term to eliminate f
14w = 56 ( divide both sides by 14 )
w = 4
Substitute w = 4 into either of the 2 equations and solve for f
Substituting into (1)
5(4) = 23 - 3f
20 = 23 - 3f ( subtract 23 from both sides )
- 3 = 3f ( divide both sides by - 3 )
1 = f
Answer:
Step-by-step explanation:
The vertex form for a quadratic equation has the following form:
Where the vertice of the equation is the point (h, k)
To transform the equation 
in its vertex forms we must find its vertex.
Be a quadratic equation of the form:
Where a, b and c are real numbers, then the vertex of the equation will be:
For the given equation:
Therefore the vertice is:
Now we substitute x = 6 into the equation and find the value of k.
Therefore the vertice is: (6, -16)
And the equation is:
Wah..I need to ask my bro to answer this.. Brb
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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The association is negative as the line goes down
