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3 years ago

Helpeleleeplpl3pel!!!!!!!!!!!!!!!!!!!!!!1

Mathematics

2 answers:

likoan [24]3 years ago

4 0

Answer: D

Step-by-step explanation:

Since the scale factor is 4:1, you need to divide each side by 4.

10 / 4 = 2.5

12 / 4 = 3

Also you can clearly rule out answer choices b and c because they just don’t make since since the object is smaller than the scale drawing.

Kryger [21]3 years ago

3 0

Answer:

im guessing D sorry if wrong

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A line which has an undefined slope is _____.

erastovalidia [21]

Answer:

c, vertical

Step-by-step explanation:

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3 years ago

Read 2 more answers

The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped

kakasveta [241]

Check the picture below.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}$

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

$\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}$

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill$

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0

3 years ago

Help me pls pls pls pls

bogdanovich [222]

Answer:

It has to be 21 2/3,A

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3 years ago

Determine which of the lines if any are parallel or perpendicular?

Tcecarenko [31]

Answer:

y=6x-2 is perpendicular to the 6y=-x+7

y=6x+1 is parallel to the y=6x-2

Step-by-step explanation:

if product of two lines gradient is -1 than lines are perpendicular

gr y=6x-2

y=mx+c m=gradient

1)m=6

2)m=-1/6

3)m=6

if gradients of 2 lines are equal they are paralel

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3 years ago

How do u round 23.569 to the hundredths place<br><br>

Oksana_A [137]

You would go right of the decimal 2nd number, then decide wether or not the 3rd number after the decimal is 5 or up, the 2nd number gets rounded up, if it’s 1-4 it gets rounded down

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3 years ago