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mojhsa [17]
3 years ago
9

Creat a number that is less than 3 hundred thousands, 7 ten-thousands, 5 thousands, 2 hundreds, 1 ten.

Mathematics
1 answer:
frozen [14]3 years ago
5 0
Ok to create a number less than 3 hundred thousand, 7 ten-thousands, 5 thousands, 2 hundreds and 1 ten, we need to know the place values of large numbers.
If it is less than 3 hundred thousand:
There would be 6 decimal places or: > 300,000

7 ten thousands:
70,000

5 thousand:
5,000

1 ten:
10

Join together all these numbers to get something like:
275,010

~I hope this helps!~ 
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Find the midpoint of the line segment joining the points (-3,-2) and (-7,5)
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Answer:

The midpoint is (-5,1.5)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates of the endpoint and divide by 2

( -3+-7)/2 = -10/2 = -5

To find the y coordinate of the midpoint, add the y coordinates of the endpoint and divide by 2

( -2+5)/2 = 3/2 = 1.5

The midpoint is (-5,1.5)

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3 years ago
Please help....title of the work assignment...WHERE DOES THE DECIMAL GO USING ESTIMATION WHEN DIVIDING DECIMALS.....
ycow [4]

The correct equation of 146 ÷ 7 = 20857 is 146.0 ÷ 7.0 = 20.857

<h3>How to divide the decimals?</h3>

The equation is given as:

146 ÷ 7 = 20857

The above equation is wrong.

The equation can be rewritten as:

146.0 ÷ 7.0 = 20857

The significant digits in 146.0 and 7.0 are 3 and 1, respectively.

3 - 1 = 2

This means that

So, the decimal place in the result must be after the second digit.

So, we have:

146.0 ÷ 7.0 = 20.857

Using the above highlights, we have:

146 ÷ 0.7 = 208.57

1.46 ÷ 7 = 0.20857

14.6 ÷ 0.7 = 20.857

1460 ÷ 70 = 20.857

The reasoning behind the above equations is that the decimal position in the results is dependent on the decimal positions in the dividend and divisor

Read more about dividing decimals at:

brainly.com/question/311920

#SPJ1

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2 years ago
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7 0
1 year ago
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Zarrin [17]
{ 9 } ∉ S. Answer C is not correct.
If subset A represent spinning a number less than 4, its sample space is
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Answer:
True statements are;
A ) S = { 1, 2, 3, 4, 5, 6, 7, 8 }.
B )  If A is a subset if S, A could be { 1, 2, 3 }.
E ) If a subset A represents the complement of spinning an odd number, its sample space is A = { 2, 4, 6, 8 }. 
3 0
3 years ago
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