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ladessa [460]
3 years ago
8

Rewrite the equation y=2|x−2|+4 as two linear functions f and g with restricted domains.

Mathematics
2 answers:
Olegator [25]3 years ago
8 0

Answer:

f(x) = -2x + 8, x < 2

g(x) = 2x, x 》2

Step-by-step explanation:

|x - 2| is:

x - 2, for x 》2

-x + 2, for x < 2

For x < 2,

f(x) = 2(-x + 2) + 4

f(x) = -2x + 8

For x 》2,

g(x) = 2(x - 2) + 4

g(x) = 2x

alexandr1967 [171]3 years ago
8 0

Answer:

f(x) = -2x + 8, x < 2

g(x) = 2x, x 》2

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miv72 [106K]

Answer:

B) 1x10^6

Step-by-step explanation:

the answer is B just subtract the exponents

3 0
3 years ago
A flower bed has the shape of a rectangle 8 yards long and 3 yards wide. What is its area in square feet?
Anika [276]

Answer:

the answer is 216 square feet because if you multiply 8 ×3=24 and 24×9=216.

3 0
3 years ago
Suppose that the probabilities are 0.4, 0.3, 0.2, and 0.1, respectively, that 0, 1, 2, or 3 power failures will strike a certain
defon

Answer:

mean = 1 power failure

variance = 1 (power failure)²

Step-by-step explanation:

Since the mean is computed as

mean = E(x) = ∑ x * p(x) for all x

then for the random variable x=power failures , we have

mean = ∑ x * p(x) = 0 * 0.4 + 1* 0.3 + 2*0.2 + 3* 0.1 = 1 power failure

since the variance can be calculated through

variance =  ∑[x-E(x)]² * p(x) for all x

but easily in this way

variance = E(x²) -  [E(x)]² , then

E(x²) = ∑ x² * p(x) = 0² * 0.4 + 1²* 0.3 + 2²*0.2 + 3²* 0.1 = 2 power failure²

then

variance = 2 power failure² - (1 power failure)² = 1 power failure²

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3 years ago
If n is an integer and can be written in expanded form....
aksik [14]
Log(10^-3) = log(0.001) = -3, and there are 3 zeros inclusive of the 0 before the decimal.
4 0
3 years ago
For the real-valued functions f(x)=2x+3 and g(x)=√x-5, find the composition fog and specify its domain using interval notation.
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Find fog

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For real range the domain

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Domain is [5,oo)

7 0
2 years ago
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