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2 years ago

Find parametric equations through point P=(2,2,7) in the direction of the vector v = (44, 14, -20)?

Mathematics

1 answer:

ycow [4]2 years ago

5 0

9514 1404 393

Answer:

(x, y, z) = (2+44t, 2+14t, 7-20t)

Step-by-step explanation:

One way to write parametric equations for line L is ...

L = P + t·v

where P is the given point and v is the given direction vector. Using that form, we have ...

(x, y, z) = (2+44t, 2+14t, 7-20t)

If you like, you can remove a common factor of 2 from the coefficients of t.

(x, y, z) = (2+22t, 2+7t, 7-10t)

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3 years ago

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ruslelena [56]

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3 years ago

You are swinging a bucket in a circle at a velocity of 7.8 ft/s. The radius of the circle you are making is 1.25 ft. The acceler

Ksju [112]

Given that,

velocity, v = 7.8 ft/s

Radius, r = 1.25 ft

To find,

a. What is the acceleration of the bucket?

b. What is the velocity if the acceleration is 25 ft/sec²?

Solution,

(a) The centripetal acceleration is given by :

$a=\dfrac{v^2}{r}$

Put v = 7.8 ft/s and r = 1.25 ft

$a=\dfrac{(7.8)^2}{1.25}\\\\=48.672\ ft/s^2$

(b) Put a = 25 ft/s² to find velocity.

$v=\sqrt{ar} \\\\v=\sqrt{25\times 1.25} \\\\v=5.59\ ft/s$

Hence, this is the required solution.

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2 years ago