The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
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Answer:
-5/7
Step-by-step explanation:
When you divide fractions, you flip the second fraction, then multiply.
So it becomes -25/28 x 4/5.
This equals -100/140 which reduces to -5/7.
Answer:
Step-by-step explanation:
I got you kiddo
You do 2*d - 2*5 = 8 which is 2d-10=8 ------> 2d=8+10 and you do d=18/2 which d = 9
Check the picture below.
the segment LOJ is a diameter, and therefore the arcLCJ made by that diameter will have a central angle of 180°.
that simply means that the arcLC is 180 - 94, or 86°.
the ∡LJC is an inscribed angle that is intercepting the arcLC, and therefore, by the inscribed angle theorem, it'll be half of arcLC.