Answer:
Gradient of Line ⊥ to AB = m = 3
B) y = 3x+11
Step-by-step explanation:
A) <u><em>Firstly, finding the slope of AB</em></u>
Gradient =
Gradient =
Gradient =
Gradient =
Gradient =
<u><em>Now, the line has a gradient of negative reciprocal to this one which is perpendicular to AB</em></u>
So,
Gradient of Line ⊥ to AB = m = 3
B) <u><em>Equation of line ⊥ to AB:</em></u>
Gradient = m = 3
Now, Point = (x,y) = (-2,5)
So, x = -2, y = 5
<u><em>Putting this in slope-intercept form to get b</em></u>
=>
=> 5 = (3)(-2) + b
=> 5+6 = b
=> b = 11
<em><u>Now, Putting m and b in the slope intercept form to get the required equation:</u></em>
=>
=> y = 3x+11
Answer:
B
Step-by-step explanation:
∠ 4 and ∠ 5 are alternate interior angles and are congruent, thus
∠ 5 = 95° → B
Answer:
3rd answer down
Step-by-step explanation:
ok so you take the median of all the #'s which turns out to be 126.5 and that is where your bar should point to in the box, then you should start with 105, and your last bit of the line should end at 150, the start of your box should start at the median of 105 and 117, and the end of your box should stop at the median of 145 and 150.
The answer to that would be 118.75