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zimovet [89]
2 years ago
12

Use the coordinates of the labeled point to find the point slope equation of the line

Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
4 0

Answer:

D. y + 1 = -2(x - 2)

Step-by-step explanation:

Point-slope form equation is given as y - b = m(x - a), where,

(a, b) = a point of the graph.

m = slope of the graph

Find the slope of the graph:

Slope = \frac{rise}{run} = \frac{-4}{2} = -2

Using the point (2, -1) and the slope, m, = -2, we can derive the equation in point-slope form by substituting a = 2, b = -1, and m = -2 into y - b = m(x - a).

✅The equation would be:

y - (-1) = -2(x - 2)

y + 1 = -2(x - 2)

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Vector A has a magnitude of 2.00 m and vector B has a magnitude of 5.00 m. If the direction of each vector is unknown, what is t
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C it look and is more right than the others
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3 years ago
Find the length of diagonal AV in a three-dimensional figure.​
katovenus [111]

Answer:

C. 13

Step-by-step explanation:

Apply pythagorean theorem.

Thus:

Diagonal AV = √(12² + 5²)

AV = √(144 + 25)

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6 0
2 years ago
Suppose the average tread-life of a certain brand of tire is 42,000 miles and that this mileage follows the exponential probabil
Ahat [919]

Answer: The probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

Step-by-step explanation:

The cumulative distribution function for exponential distribution is :-

P(X\leq x)=1-e^{\frac{-x}{\lambda}}, where \lambda is the mean of the distribution.

As per given , we have

Average tread-life of a certain brand of tire :  \lambda=\text{42,000 miles }

Now , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles will be :

P(X\leq 65000)=1-e^{\frac{-65000}{42000}}\\\\=1-e^{-1.54761}\\\\=1-0.212755853158\\\\=0.787244146842\approx0.7872

Hence , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

8 0
3 years ago
the size of the second application is 3.45 MB less than he first application. What is the size of the second application
mr_godi [17]

The size of the second application given the size of the first application and the expression ( x - 3.45 mb) for the size of the second application is 293.55 MB.

<h3>Equation</h3>

Let

  • Size of the first application = x

  • Size of the second application= x - 3.45 mb

For instance,

if the size of the first application is 297 MB

Size of the second application= x - 3.45 mb

= 297 MB - 3.45 MB

= 293.55 MB

Therefore, the size of the second application given the size of the first application and the expression for the size of the second application is 293.55 MB

Learn more about equation:

brainly.com/question/2972832

#SPJ1

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What is a equivalent expression for 4(x-2)
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