If 8 students had 1,1/4 brownies each how manym did they start with?

Mathematics

1 answer:

denis-greek [22]3 years ago

4 0

You need to multiply 8 by one and 8 by one fourth so the answer is ten

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If a^(b/4) = 16 for positive integers a and b, what is one possible value of b?.

Verizon [17]

Answer:

Step-by-step explanation:

$a^{(\dfrac{b}{4})} = 16\\\\\\Both \ sides \ raise \ to \ 4\\\\(a^{\dfrac{b}{4}})^{4} = 16^{4}\\\\a^{\dfrac{b}{4}*4}=16^{4}\\\\a^{b}=16^{4}$

b = 4

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pickupchik [31]

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What is m∠2 + m∠3? <br> m∠2 + m∠3 =?

Serga [27]

Let's start with m∠1. m∠1 <em>has </em>to be 90º because line segment AB is perpendicular with line segment AC, as it shows a right angle symbol on the angle beside m∠1. Now that we know that, it will be much easier to find m∠2 and m∠3 because m∠1, m∠2 and m∠3 are part of the triangle formed in the middle, and all angles in a triangle add up to 180º. 180-90 is 90, therefore, m∠2 +m∠3=90º so all three angles add up to 180º. You don't even have to find the specific angle measurements.

Hope this helps. I also attached a (rather poorly edited) image.