Answer:
The average value of
over the interval
is
.
Step-by-step explanation:
Let suppose that function
is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of
over the interval
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)



The average value of
over the interval
is
.
Answer:
B. y = -3/8x - 4
Step-by-step explanation:
Given equation: 3x - 8y = 12
Find a parallel line that matches one of the equations shown.
First, find the slope by solving for y:
3x - 8y = 12
8y = -3x + 12
y = -3/8x + 12/8
y = -3/8x + 3/2
Slope m = -3/8
Since the slope of a line parallel is the same slope, the only equation that fits the conditions is B because in the form y = mx + b, m = -3/8
All you have to do is move the denominator on the other side, by multiplying.
a-10
------- = -9
20
multiply 20 x -9
= -180
then it becomes a-10=-180
+10 +10
a=-170
Since it is a 45-45-90 right triangle, the formula is:
Hypotenuse= sqrt2 * leg
Since you know hypotenuse = 9sqrt2 the leg has to be 9