<span>TLDR: Equation is 5(10 + x) = 6x. x = 50, so Sheila deposited $50 each 6 trips. Sherri deposited $60 each 5 trips. Both of them deposited $300 in total.

</span>Sherri deposited $10 more into her bank account than Sheila each 5 times. Expression: 5(x + 10).

Sheila deposited money 6 times
Expression: (6)(x) or 6x

Put it all together and the equation is 5(x+10)=6x.

Solve by distributing the 5 on the right side of the equation 5(x+10) to get 5x + 50 = 6x. Subtract 5x on both sides of equation. 5x - 5x + 50 = 6x - 5x to get 50 = 1x. Divide by 1 on each side to isolate the variable. x = 50. Sheila paid $50 in each of her 6 deposits, so she deposited $300 in total. Check the equation by replacing x with 50.

Sherri paid $60 in each of her 5 deposits because 50 + 10 is 60. 60 by 5 is also $300.

4 0

3 years ago

Q3. Consider two identical pack of cards A and B. When one card from A is taken and shuffled with the card B, the first top card

vivado [14]

Answer:

0.02

Step-by-step explanation:

Pack A and B both consisted of 52 cards. When shuffled, 51 cards in A and 53 cards in deck B. It appears that the Top card of A left with only 51 possible cards to be taken from A (since we know the Queen hadn't moved).

The two possible cases are: probability of not taking King of Hearts (from A to B), and the other were we did.

Let K= the event of taking the King of Hearts from A to B and be $B_{K}$ the occasion being the top card of B.

$P(B_{K} )=P(K)P(B_{K} |K)+P(K^{C} )P(B_{K} |K^{C} )\\$

$=\frac{1}{51} \frac{2}{53} +\frac{50}{51} \frac{1}{53}$

$=\frac{52}{2703} \\=0.02$

8 0

3 years ago