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Lana71 [14]
3 years ago
10

GUYS PLEASE HELP!!!!

Mathematics
1 answer:
12345 [234]3 years ago
5 0
The first two equations are correct
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If f(x) = -3x+1 then f^-1(x) =
elena55 [62]

Answer:

please mark me brainliesf if it helps you

f(x) = -3x+1

or, y = -3x + 1

Interchanging the position of x and y, we get,

x = -3y +1

or, 3y = 1 - x

or, y = 1 - x /3

: . f^-1(x) = 1-x / 3

8 0
2 years ago
5x -6y=-32
erastovalidia [21]
So this question is already perfectly set up. Since the 6 and -6 cancel you’ll be left with 5x + 3x which is 8x and -32 + 48 which is 16. 8x=16. Isolate x to get that x=2. Plug 2 back into one of the equations. 5(2) -6y = -32. Solve for y now. -10-32 equals -42. Divide -42 by -6 to get 7. So the final coordinate where the two equations will intersect is (2,7)
3 0
3 years ago
Use the identity (x+y)(x^2−xy+y^2)=x^3+y^3 to find the sum of two numbers if the product of the numbers is 28, the sum of the sq
lara31 [8.8K]

Step-by-step explanation:

We have xy = 28, x² + y² = 65 and x³ + y³ = 407.

Since (x + y)(x² - xy + y²) = x³ + y³,

x + y = (x³ + y³)/(x² + y² - xy)

= (407) / [(65) - (28)]

= 407 / 37

= 11.

Hence the sum of the numbers is 11.

4 0
3 years ago
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Which of the following statements are true about the equation below?
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The correct answer is 5
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