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Lana71 [14]
3 years ago
10

GUYS PLEASE HELP!!!!

Mathematics
1 answer:
12345 [234]3 years ago
5 0
The first two equations are correct
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At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Ge
balandron [24]

Answer:

Each student ticket costs $8.33

Each adult ticket costs $15.34

Step-by-step explanation:

At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Gelvoria bought 3 student tickets and 3 adult tickets for the show and it cost her $72. How much are each type of tickets?​

s = cost of each student ticket

a = cost of adult ticket

Our system of equations:

4s + 2a = 64

3s + 3a = 71

-3(4s + 2a = 64) ==> -12s - 6a = -192

2(3s + 3a = 71) ==>     6s + 6a = 142

-12s - 6a = -192

  6s + 6a = 142

-6s = -50

/-6      /-6

s = $8.33 (the cost of each student ticket)

Now, let's find the cost of each adult ticket:

4s + 2a = 64

4(8.33) + 2a = 64

33.32 + 2a = 64

-33.32         -33.32

2a = 30.68

/2        /2

a = 15.34 (the cost of each adult ticket)

(x, y) ==> (8.33, 15.34)

Check your answer:

4s + 2a = 64

4(8.33) + 2(15.34) = 64

33.32 + 30.68 = 64

64 = 64

This statement is true

Hope this helps!

8 0
2 years ago
4000
Airida [17]

Answer:

$1000 ; 500 ; 1000 ; y = 500x + 1000

Step-by-step explanation:

From the graph, the initial deposit which started the savings account is $1000 ; this is the value on the y - intercept, the value in the account at time or period = 0.

The slope :

x1 = 0 ; y1 = 1000

x2 = 6 ; y2 = 4000

Slope = Rise / Run

Rise = y2 - y1 = 4000 - 1000 = 3000

Run = x2 - x1 = 6 - 0 = 6

Hence,

Slope = 3000 / 6

Slope = 500

y - intercept = 1000 (from. Graph)

Equation in slope intercept form:

General form : y = mx + c

m = slope ; c = intercept

Equation is written as ;

y = 500x + 1000

5 0
3 years ago
Modeling Compound Interest In Exercise, complete the table for an account in which interest is compounded continuously.
Mademuasel [1]

Answer:

This problem requires us to calculate, the value of investment after 10 and 25 years, and also tell the time after which intial investment amount will double. Investment rate and initial investment amount is given in the question.

Value of investment after 10 year = 600(1+8%)^10 = $ 1,295

Value of investment after 25 year = 600(1+8%)^25 = $ 4,109

Time after which investment amount double (n)

1200 = 600 (1.08)^n

Log 2 = n log 1.08

n = 9 years

6 0
3 years ago
The time required to make one bouquet in a flower stall is of an hour. Find the time
solong [7]

Answer:

13.5 hours

the fitness gram pacer test is a multi stage aerobic capacity test that progressivly gets more difficult as it continues

5 0
3 years ago
Read 2 more answers
Will mark brainliest has to be correct. ​
yarga [219]
Answer:
x=12
Step by step explanation:

7 0
3 years ago
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