You would have to determine if<span> the following </span>lengths<span> make an </span>acute<span>, right or </span>obtuse triangle<span>. Plug in each set of </span>lengths<span> into the Pythagorean Theorem.</span>
θ\ 6 degrees
\
\ so the θ= 180-90-6 =84 degrees so we need to find x
20m \ tan (84)=x/20
____ \ x=20 tan(84)
x x=190.287
I hope this helps you
2a.2a+1.2a-3.2a-3.1
4a^2+2a-6a-3
4a^2-4a-3
The sum of the angles of a quadrilateral is 360 degrees. So P+Q+R is 206, 360 - 206 = 154 degrees, the measure of angle S.
The four triangles, AQB, BRC, CSD, and DPA are all isosceles. So angle QBA = angle BAQ, etc. We find QBA = (180-24)/2 or 78 degrees.
RBC = (180-114)/2 = 33 degrees.
180 - (78 + 33) is the measure of angle B: 69 degrees.
The student should be able to see how to calculate the missing information from this.
