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spayn [35]
3 years ago
13

2(x + 4) - 5 = 3x + 3

Mathematics
2 answers:
lora16 [44]3 years ago
4 0

Answer:

x=0

Step-by-step explanation:

Use Cymath it helps with problems like that... www.cymath.com

OverLord2011 [107]3 years ago
3 0

Answer:

x=0

Step-by-step explanation:

2(x+4)- 5 = 3x+3

Distribute

2x+8-5 = 3x+3

Subtract x values

8-5 = x+3

3 = x+3

Final Subtraction

x = 0

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satela [25.4K]

Answer:

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b. 28.83

Step-by-step explanation:

4.25 x 5 = 21.25

3.79 x 2 = 7.58

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3 years ago
Please help!! I don’t understand this
cricket20 [7]
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if a sequence is defined recursively by f(0)=4 and f(n+1)= -3f(n+1)=-3f(n)+1 for n≥0, then f(3) is equal to? DESPERATELY NEED HE
muminat

f(3) is equal to -101.

<u>Step-by-step explanation</u>:

  • The sequence is followed by f(0)=4
  • The given expression is f(n+1)= -3f(n)+1

Put n=0,

f(0+1)= -3f(0)+1

f(1)= -3(4)+1

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Put n=1,

f(1+1)= -3f(1)+1

f(2)= -3(-11)+1

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5 0
3 years ago
Some help figuring out the answer?? Also explain a little how you got there
ipn [44]

9514 1404 393

Answer:

  x = 10·cos(θ) -4·cot(θ)

Step-by-step explanation:

Apparently, we are to assume that the horizontal lines are parallel to each other.

The relevant trig relations are ...

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

If the junction point in the middle of AB is labeled X, then we have ...

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  cos(θ) = x/XA   ⇒   XA = x/cos(θ)

Then ...

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Substituting for BX and XA using the above relations, we get

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Solving for x gives ...

  x = (10 -4/sin(θ))·cos(θ)

  x = 10·cos(θ) -4·cot(θ) . . . . . simplify

_____

We used the identity ...

   cot(θ) = cos(θ)/sin(θ)

6 0
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marusya05 [52]
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