Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer:
Where is it I don't see it?
Step-by-step explanation:
Answer:
15ft
Step-by-step explanation:
a^2 + b^2 = c^2
12 or 9 can equal to b or a
12^2 + 9^2 = c^2
144 + 81 = c ^2
225 = c^2
Square root of 225
15 = c
Student B:
1/2 / 4
= 1/2 x 1/4
= 1/8
student A:
2/3 / 6
= 2/3 x 1/6
= 1/9
student C:
4/5/ 8
= 4/5 x 1/8
= 1/10
answer
student B: 1/8 of a mile per minute
student A: 1/9 of a mile per minute
student C: 1/10 of a mile per minute
Use Photomath it graphs too
