Answer: ![sds\\ \\ x^{2} \geq \int\limits^a_b {x} \, dx \lim_{n \to \infty} a_n \geq \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right. x^{2} \lim_{n \to \infty} a_n \pi \neq \sqrt{x} \neq](https://tex.z-dn.net/?f=sds%5C%5C%20%5C%5C%20x%5E%7B2%7D%20%5Cgeq%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%5Cgeq%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%5Cpi%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20x%5E%7B2%7D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%5Cpi%20%5Cneq%20%5Csqrt%7Bx%7D%20%5Cneq)
Step-by-step explanation:i need the think points
Answer:
(x - 3) x + 2
Step-by-step explanation:
1/4 (2 x - 3)^2 - 1/4
Hi there! :)

Find the central angle using a ratio in regards to angle and circumference.
The radius is 27 units, so use the following equation to calculate circumference:
C = 2rπ
Therefore:
C = 2(27)π = 54π
Since we have the total circumference, we can write the following proportion:

Cross multiply:
54πx = 6480π
Divide both sides by 54π to isolate for x:
x = 120°
The answer to your problem is 2.5.
Answer:
<h3>The solution is 480 bricks.</h3>
Step-by-step explanation:
We are given that number of rows of bricks in a wall = 15 rows.
Number of bricks in a row = 32 bricks.
In order to find the total number of bricks, we need to multiply number of rows with number of bricks in a row.
Total number of bricks in 15 rows = 15 × 32 = 480 bricks.
Therefore, will Chin-li will need 480 bricks.
<h3>The solution is 480 bricks.</h3>