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Sidana [21]
3 years ago
12

Find the x- and y-intercept of the line. –3x + 9y = 18

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0
Line <span>–3x + 9y = 18
</span>
x-intercept when y = 0
so -3x = 18
        x = -6

y-intercept when x = 0
so 9y = 18
       y = 2

answer
x-intercept (-6,0)
y-intercept (0, 2)

hope it helps
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Answer:

26 \frac{1}{4}

Step-by-step explanation:

First we turn them into improper fractions

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then we multiply it

-\frac{7}{2}*-\frac{45}{4}=\frac{315}{12}=26\frac{1}{4}

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y = -3x - 2

Step-by-step explanation:

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(12)3=36

Step-by-step explanation:

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This scatter plot show the relationship between the temperature and amount of sales at a store. The line of best fit is shown on
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3 years ago
A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome
Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

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P (A remaining passenger will arrive), <em>p</em> = 0.52

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.

(1)

Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

=P(X

Thus, the probability that the flight has empty seats is 0.4625.

4 0
3 years ago
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