No no dont take any bad decisions god know what to do there is a bright future in front of u
        
                    
             
        
        
        
Answer:
Add 1 to both sides of the equation.
Subtract 3 from both sides of the equation.
Step-by-step explanation:
The inverse of a function refers to that function that tends to undo another function.
If we intend to find the inverse of the function, f(x) = 3+ V2 - 1, we have to first add 1 to both sides of the equation and subsequently subtract 3 from both sides of the equation before taking the square root of both sides to obtain the inverse function.
Step-by-step explanation:
I hope this helps you :)
<em><u>-KeairaDickson</u></em>
 
        
             
        
        
        
Step-by-step explanation:
This time round, use SOH method (Sin angle = Opposite/Hypotenuse)
given Opposite = 7
Hypotenuse = 10

 
        
             
        
        
        
Answer:
Equation of tangent plane to given parametric equation is:

Step-by-step explanation:
Given equation
        ---(1)
---(1)
Normal vector  tangent to plane is:


Normal vector  tangent to plane is given by:
![r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]](https://tex.z-dn.net/?f=r_%7Bu%7D%20%5Ctimes%20r_%7Bv%7D%20%3Ddet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5Ccos%28v%29%26sin%28v%29%260%5C%5C-usin%28v%29%26ucos%28v%29%261%5Cend%7Barray%7D%5Cright%5D)
Expanding with first row

at u=5, v =π/3
                    ---(2)
 ---(2)
at u=5, v =π/3 (1) becomes, 
                  
                 
                 
From above eq coordinates of r₀ can be found as:
             
From (2) coordinates of normal vector can be found as
              
   
Equation of tangent line can be found as:
   