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Arturiano [62]
3 years ago
5

Which radical expressions are equivalent to 7 5/4

Mathematics
2 answers:
Troyanec [42]3 years ago
4 0

Answer: = √(22·2) (x2·x) y2 (z4. z) EXAMPLE Put 3√24 x6 y5 z10 in standard form. EXAMPLE Put 3√− 2 x11 y4 in standard form. EXAMPLE Put 4√64 x4 y10 in standard form. DEFINITION Radical expressions are said to be similar when they have the same radical index and the same radicand. EXAMPLES 1. The redial expressions 3 √2 and 5 √2 are similar. 2.

Step-by-step explanation:

Yw and mark me brainiest

klemol [59]3 years ago
4 0

Answer:

7 4/7

Step-by-step explanation:

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How many positive integers less than 1000 are divisible by both 7 and 11?
AlladinOne [14]
220-12=208 is your answer 
6 0
3 years ago
Solve for the value of x. Show each of your steps. 7y=8x - 14 ; y= 6
svetlana [45]
When y=6, then in equation 7y=8x-14 we write 6 instead of y:
7×6=8x-14
42=8x -14
8x-14=42 (now we add 14 to both sides of equation)
8x=56 (now we divide by 8 both sides of equation)
x=7

Answer: x=7
4 0
3 years ago
Read 2 more answers
Can anyone tell me what "x" equals. Thx.
Lapatulllka [165]

-6x-1=23

=> -6x=1+23

=> -6x=24

=> x= 24/-6

=> x= -4

Hope it helps!

8 0
3 years ago
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Can someone walk me through how to do this, please? I forgot. Solve for a and z. x^8⋅x^3=ax^z
Sliva [168]
Solve for a by simplifying both sides of the equation, then isolating the variable.
a=x^11-z
Solve for z by creating equivalent expressions in the equation that all have equal bases, then solve for z. 
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7 0
4 years ago
(2+3i)(1-2i)<br><br> What is the product of the complex number
igomit [66]

Answer:

(2+3i)(1-2i)  = (8-i)

Step-by-step explanation:

The given complex number is :

Z = (2+3i)(1-2i)

We need to find the product of the complex number

Z=2(1)+2(-2i)+3i(1)-6i^2\\\\=2-4i+3i-6i^2

We know that, i^2=-1

Z=2-i-6(-1)\\\\=2-i+6\\\\=8-i

Hence, the product of the complex number is (8-i).

3 0
3 years ago
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