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maks197457 [2]
4 years ago
6

Solve the equation by completing the square

Mathematics
1 answer:
Andrews [41]4 years ago
4 0

Answer:

b1=2\sqrt{46} +10

b2=10-2\sqrt{46}

Step-by-step explanation:

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pychu [463]

\bf \begin{cases} x^2+y^2=400\\ \boxed{y}=x-28 \end{cases}\qquad \stackrel{\textit{substituting on the 1st equation}}{x^2+\left( \boxed{x-28} \right)^2=400} \\\\\\ x^2+(x^2-56x+28^2)=400\implies x^2+x^2-56x+28^2=400 \\\\\\ 2x^2-56x+784=400\implies 2x^2-56x+384=0 \\\\\\ 2(x^2-28x+192)=0\implies x^2-28x+192=0 \\\\\\ (x-16)(x-12)=0\implies x = \begin{cases} 16\\ 12 \end{cases}

now that we know what are the x-values, what are the y-values? well, we can just use the 2nd equation, since we know that y = x - 28, then

\bf y = x - 28\implies \stackrel{\textit{when x = 16}}{y = 16 - 28}\implies y = -12 \\\\\\ y = x - 28\implies \stackrel{\textit{when x = 12}}{y = 12 - 28}\implies y = -16 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{x}{16}~~,~~\stackrel{y}{-12})\qquad,\qquad (\stackrel{x}{12}~~,~~\stackrel{y}{-16})~\hfill

7 0
3 years ago
4(610−15)+0.4= ? please help
cricket20 [7]
4(595)+0.4 =
2380 = 0.4 = 
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I hope this helps 
5 0
3 years ago
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kolezko [41]

Answer:

0.0009

Step-by-step explanation:

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Hope this helps!
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Pavlova-9 [17]
The answer is c cccccc the answ er is c
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