Although an 8mm or 16mm would be better cost wise, I personally would use a 35 mm camera for this type of film. The 35mm is the only camera that would work well on a big screen. It is a rather expensive camera but no other camera could fit on the big screen.
o_num = input ("Please enter the amount of \"o\": ")
zero_num = input ("Please enter the amount of zeros: ")
i = 0
while i < o_num and i < zero_num:
repeat_o = "Hell" + o_num
repeat_zero = repeat_o + zero_num
i+=1
print (repeat_zero)
Answer:
photoshop
Explanation:
(if there are answer choices pls comment them and I'll pick an answer from them, but this is just my best guess. : )
Answer:
The method definition to this question can be given as:
Method definition:
double max(double x, double y) //define method with double parameter
{
if (x>=y) //check condition.
return x; //return value
else
return y; //return value
}
double max(int x, int y) //define method with integer parameter
{
if (x>=y) //check condition
return x; //return value
else
return y; //return value
}
double max(char x, char y) //define method with char parameter
{
if (x>=y) //check condition
return x; //return value
else
return y; //return value
}
Explanation:
The above method definition can be described as below:
- In the first method definition first, we define a method that is "max()". In this method we pass two variables as a parameter that is "x and y" and the datatype of this is double. Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
- In the second method definition, we define a method that is same as the first method name but in this method, we pass two integer variable that is "x and y". Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
- In the third method definition, we define a method that is same as the first and second method name but in this method, we pass two char variable that is "x and y". Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
Answer:
def sum_digits(number):
total = 0
if 1 <= number <= 999:
while number > 0:
r = int (number % 10)
total +=r
number /= 10
else:
return -1
return total
print(sum_digits(658))
Explanation:
Write a function named sum_digits that takes one parameter, number
Check if the number is between 1 and 999. If it is, create a while loop that iterates until number is greater than 0. Get the last digit of the number using mudulo and add it to the total. Then, divide the number by 10 to move to the next digit. This process will continue until the number is equal to 0.
If the number is not in the given range, return -1, indicating invalid range.
Call the function and print the result
